๐Ÿ’ก Algorithm

[SQL] ๋™๋ช… ๋™๋ฌผ ์ˆ˜ ์ฐพ๊ธฐ - GROUP BY (Lv. 2)

jcowwk 2025. 4. 2. 21:48

JAVA ๊ธฐ๋ณธ ๊ฐœ๋…


1. ๋ฌธ์ œ

2. ํ’€์ด


1. ๋ฌธ์ œ

 

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

SW๊ฐœ๋ฐœ์ž๋ฅผ ์œ„ํ•œ ํ‰๊ฐ€, ๊ต์œก, ์ฑ„์šฉ๊นŒ์ง€ Total Solution์„ ์ œ๊ณตํ•˜๋Š” ๊ฐœ๋ฐœ์ž ์„ฑ์žฅ์„ ์œ„ํ•œ ๋ฒ ์ด์Šค์บ ํ”„

programmers.co.kr

 

2. ํ’€์ด

SELECT NAME, COUNT(NAME) AS 'COUNT' 
FROM ANIMAL_INS 
GROUP BY NAME 
HAVING COUNT(NAME) > 1 
ORDER BY NAME

 

- COUNT(NAME) AS 'COUNT'

๊ฐ ์ด๋ฆ„์ด ๋ช‡ ๋ฒˆ ๋“ฑ์žฅํ–ˆ๋Š”์ง€ ๊ณ„์‚ฐํ•ฉ๋‹ˆ๋‹ค.

 

- GROUP BY NAME

ํ•ด๋‹น ์ด๋ฆ„์ด ์‚ฌ์šฉ๋œ ํšŸ์ˆ˜๋ฅผ ๊ตฌํ•˜๊ธฐ ์œ„ํ•ด ๊ฐ™์€ ์ด๋ฆ„๋ผ๋ฆฌ ๊ทธ๋ฃนํ™”ํ•ฉ๋‹ˆ๋‹ค.

 

- HAVING COUNT(NAME) > 1

ํ•œ ๋ฒˆ ์ด์ƒ ์‚ฌ์šฉ๋œ ์ด๋ฆ„์„ ํ•„ํ„ฐ๋งํ•ฉ๋‹ˆ๋‹ค.


๋ฌธ์ œ๊ฐ€ ์žˆ์œผ๋ฉด ๋Œ“๊ธ€ ๋‚จ๊ฒจ์ฃผ์„ธ์š” !

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